How many grams of lithium sulfate (#Li_2SO_4#) are required to dissolve in 459 g of water to make a 1.23 m solution?

1 Answer
Jun 15, 2016

Answer:

I assume you want #"molal"# NOT #"molar"# concentration.

Explanation:

We want a #1.23*mol*kg^-1# solution with respect to #Li_2SO_4#. Here, we deal with a molal concentration.

#"moles of lithium sulfate"/"kilograms of solvent"# #=# #1.23*mol*kg^-1#

Thus #"moles of lithium sulfate"#

#=# #0.459*kgxx1.23*mol*kg^-1# #=# #0.565*mol#

We require a mass of #0.565*molxx109.94*g*mol^-1# #=# #62.12*g#.

This site reports the solubility of lithium sulfate in water. I have not gone thru it. Your given problem may be physically unrealistic.