How many grams of #NaOH# are in 500 mL of 0.175 M #NaOH# solution?

1 Answer
anor277
Jul 2, 2016

Under #4.0*g# of sodium hydroxide.

Explanation:

#"Concentration"# #=# #"Moles"/"Volume of solution"#.

Thus #n_"NaOH"# #=# #500xx10^-3cancelLxx0.175*mol*cancel(L^-1)=0.0875*mol#. (i.e., #"moles"# #=# #"volume "xx" concentration"#); this is certainly consistent dimensionally.

We thus have a quantity in moles of #NaOH#. All we have to do is multiply this molar quantity by the molar mass:

#40.00*g*cancel(mol^-1)xx0.0875*cancel(mol)# #=# #??g#

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