How many grams of NaOH are in 500 mL of 0.175 M NaOH solution?

Jul 2, 2016

Under $4.0 \cdot g$ of sodium hydroxide.

Explanation:

$\text{Concentration}$ $=$ $\text{Moles"/"Volume of solution}$.

Thus ${n}_{\text{NaOH}}$ $=$ $500 \times {10}^{-} 3 \cancel{L} \times 0.175 \cdot m o l \cdot \cancel{{L}^{-} 1} = 0.0875 \cdot m o l$. (i.e., $\text{moles}$ $=$ $\text{volume "xx" concentration}$); this is certainly consistent dimensionally.

We thus have a quantity in moles of $N a O H$. All we have to do is multiply this molar quantity by the molar mass:

$40.00 \cdot g \cdot \cancel{m o {l}^{-} 1} \times 0.0875 \cdot \cancel{m o l}$ $=$ ??g