# How many grams of NaOH is produced from 1.20 x 10^2 grams of Na_2O? Na_2O + H_2O -> 2NaOH

##### 1 Answer
Jul 20, 2014

If we begin the problem with 120. grams of $N {a}_{2} O$ and we are trying to find the mass of $N a O H$ that can be produced, this is a gams to grams stoichiometry problem.

$g r a m s \to m o l s \to m o l s \to g r a m s$

$120. g N {a}_{2} O$ x $\frac{1 m o l N {a}_{2} O}{62. g N {a}_{2} O}$ x $\frac{2 m o l N a O H}{1 m o l N {a}_{2} O}$ x $\frac{40. g N a O H}{1 m o l N a O H}$ =

the gfm of $N {a}_{2} O$ is (2 x 23 + 1 x 16 = 62)
the gfm of $N a O H$ is (1 x 23 + 1 x 16 + 1 x 1 = 40)

The mole ratio from the balanced chemical equation is 2 moles of $N a O H$ for every mole mole of $N {a}_{2} O$.

The final calculation is
120 x 2 x 40 / 62 = 154.8387

The final solution comes to $154. g r a m s N a O H$

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I hope this was helpful.
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