How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH#

1 Answer
Jul 20, 2014

If we begin the problem with 120. grams of #Na_2O# and we are trying to find the mass of #NaOH# that can be produced, this is a gams to grams stoichiometry problem.

#grams -> mols -> mols -> grams#

#120. g Na_2O# x #(1 mol Na_2O) / (62. g Na_2O)# x #(2 mol NaOH) / (1 mol Na_2O)# x #(40. g NaOH) / (1 mol NaOH)# =

the gfm of #Na_2O# is (2 x 23 + 1 x 16 = 62)
the gfm of #NaOH# is (1 x 23 + 1 x 16 + 1 x 1 = 40)

The mole ratio from the balanced chemical equation is 2 moles of #NaOH# for every mole mole of #Na_2O#.

The final calculation is
120 x 2 x 40 / 62 = 154.8387

The final solution comes to #154. grams NaOH#


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