Question

How many grams of nitrogen are needed to produce 100 grams of ammonia gas?

Answer 1

Approx. `3*mol` `"dinitrogen gas"` `~=` `80*g`

Explanation:

`1/2N_2(g) + 3/2H_2(g) rarr NH_3`

`"Moles of ammonia"=(100*g)/(17.03*g*mol^-1)=5.87*mol`.

And thus we need `(5.87*mol)/2xx28.02*g*mol^-1` of `"dinitrogen"` `=` `??g`