# How many grams of nitrogen are needed to produce 100 grams of ammonia gas?

Feb 4, 2017

Approx. $3 \cdot m o l$ $\text{dinitrogen gas}$ $\cong$ $80 \cdot g$
$\frac{1}{2} {N}_{2} \left(g\right) + \frac{3}{2} {H}_{2} \left(g\right) \rightarrow N {H}_{3}$
$\text{Moles of ammonia} = \frac{100 \cdot g}{17.03 \cdot g \cdot m o {l}^{-} 1} = 5.87 \cdot m o l$.
And thus we need $\frac{5.87 \cdot m o l}{2} \times 28.02 \cdot g \cdot m o {l}^{-} 1$ of $\text{dinitrogen}$ $=$ ??g