# How many grams of oxygen are produced by the decomposition of 1 mole of potassium chlorate, KClO_3 in the reaction 2KClO_3->2KCl+3O_2?

Apr 13, 2016

$\text{48g}$

#### Explanation:

${\text{2KClO"_3rarr"2KCl"+"3O}}_{2}$

This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.

Using simple proportion:

$2 \text{mol"rarr3"mol}$

$\therefore 1 \text{mol"rarr3/2"mol}$

The $\text{M"_r}$ of ${\text{O}}_{2} = 32$

$\therefore \text{mass O"_2=32xx3/2=48"g}$