How many grams of oxygen can be produced from the decomposition of 200 grams of potassium permanganate?

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Answer 1 · 2018-01-28T08:14:40

#20.2475g# of oxygen

The chemical formula of the decomposition of potassium permanganate is #2KMnO_4rarrK_2MnO_4+MnO_2+O_2#.

We must calculate how many moles of potassium permanganate reacted.

Use the formula #"moles"="given mass"/"molar mass"#

The mass of the reactant in the question is #200g#. The molar mass of the reactant is #158.034g mol^-1#

Do the math: #200/158.034=1.26555mol# of the reactant.

Look at the ratio between moles of the reactant and oxygen. They are in a #2:1# ratio. Therefore, #1.26555/2=0.632775mol# of oxygen is produced.

Rearrange the formula to find the amount of moles. The mass of produced oxygen is #0.632775*31.998=20.2475g#.