How many grams of sodium hydroxide would be needed to completely neutralize 2.8g of sulfuric acid? 2NaOH+H2SO4- Na2SO4+ 2H2O The dash is an arrow

1 Answer
anor277
Jun 17, 2018

Approx....#2*g#

Explanation:

You have already given the stoichiometric equation...

#underbrace(2NaOH(aq)+H_2SO_4(aq))_(80*g+98*g) rarr underbrace(Na_2SO_4(aq) + 2H_2O(l))_(178*g)#

Both mass and charge are BALANCED ABSOLUTELY, as indeed they must be if we purport to represent a chemical reaction.

And so #n_"sulfuric acid"=(2.8*g)/(98.08*g*mol^-1)=0.0286*mol#.

And we require TWO equiv of sodium hydroxide....i.e. a mass of...

#2xx0.0286*molxx40.0*g*mol^-1=??*g#

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