# How many grams of sodium sulfate (na2so4) are required to make 4.5 liters of a 3.0M solution?

## Molar mass of Na is 23 g/mol, S is 32 g/mol, O is 16 g/mol.

May 5, 2016

Approx $2$ $k g$ of salt are required.
If $4.5 \cdot L$ of a $3.0 \cdot m o l \cdot {L}^{-} 1$ solution are required, this is a molar quantity of $4.5 \cdot L \times 3.0 \cdot m o l \cdot {L}^{-} 1 = 13.5 \cdot m o l$.
$13.5 \cdot m o l \times 142.04 \cdot g \cdot m o {l}^{-} 1$ $=$ ??*g