# How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.5 * 10^2 grams?

$8.75$ $\text{g solute}$
If the mass of the solution is $2.5 \times {10}^{2}$ $\text{g}$, and the percentage mass of the solute is 3.50%, then the mass of the solute is
(2.5xx10^2color(white)(l)"g solution")(0.0350) = color(red)(8.75 color(red)("g solute"
You would therefore need color(red)(8.75 sfcolor(red)("grams of the solute" to prepare the solution.