# How many joules of heat would be required to heat 0.5 kg of aluminum by 2K?

Apr 18, 2017

$902$ $J$

#### Explanation:

Use the equation $Q = m c \delta T$

Where $Q =$heat flow, $m =$mass, $c =$specifc heat capacity of $A l$ and $\delta T =$change in temperature

Just looking up the specific heat capcity of aluminum off google, which is $0.902$ $\frac{J}{g \cdot C}$

Sub values in with their correct units (the change in the kelvin scale is the same in celsius)

Q=(500g)*0.902(J/(g*C))*(2 celsius)

$Q = 902$ $J$