Question

How many kilograms of solvent are there in a sample of 0.30 molal solution if the sample contains 13 moles of solute?

Answer 1

`43" Kg of solvent"`

Explanation:

The molality (`m`) is defined as: `m=n/("Kg of solvent")`,

where, `n` is the number of mole of solute.

Therefore, `"Kg of solvent"=n/m=(13cancel(mol))/(0.30cancel(mol)/(Kg))=43" Kg of solvent"`