How many kilograms of solvent are there in a sample of 0.30 molal solution if the sample contains 13 moles of solute? Chemistry Solutions Molality 1 Answer Dr. Hayek Apr 18, 2016 Answer: #43" Kg of solvent"# Explanation: The molality (#m#) is defined as: #m=n/("Kg of solvent")#, where, #n# is the number of mole of solute. Therefore, #"Kg of solvent"=n/m=(13cancel(mol))/(0.30cancel(mol)/(Kg))=43" Kg of solvent"# Related questions How do molality and molarity differ? How high can molality be? How do you calculate molality from molarity? Why is molality used for colligative properties? Why is molality independent of temperature? How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? 49.8 grams of KI is dissolved in 1.00 kg of solvent. What is the molality? 58.44 grams of NaCl and you dissolved it in exactly 2.00 kg of pure water (the solvent). What would ... What is the molality when 0.75 mol is dissolved in 2.50 L of solvent? What is the molality when 48.0 mL of 6.00 M H2SO4 are diluted into 0.250 L? See all questions in Molality Impact of this question 2285 views around the world You can reuse this answer Creative Commons License