# How many kinetic energy is possessed by a 3.5 kilograms cart traveling at 2.5 meters per second?

We use the formula, ${E}_{k} = \frac{1}{2} m {v}^{2}$
So ${E}_{k} = \frac{1}{2} \times 3.5 \times {2.5}^{2} = 10.9$ J