How many liters of ammonia would be produced from 40.0 grams of nitrogen?

1 Answer
Apr 17, 2018

#"164 L NH"_3#

Explanation:

Molar mass of #"N"_2 = "28.0 g/mol"#

Moles of #"40.0 g N"_2 = "40.0 g"/"28.0 g/mol" = "1.43 mol"#

Formation of ammonia #("NH"_3)# is given by the equation

#"N"_2 + "3H"_2 -> "2NH"_3#

From above equation we can say,
At #"STP"# one mol of #"N"_2# gives#="2 × 22.4 L NH"_3#

#"1.43 mol N"_2# will give

#1.43 cancel("mol N"_2) × ("2 × 22.4 L NH"_3)/(1 cancel("mol N"_2)) = color(blue)("164 L NH"_3)#