# How many milliliters of a 25% (m/v) #NaOH# solution would contain 75 g of #NaOH#?

##### 2 Answers

#### Answer:

#### Explanation:

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A solution's *mass by volume percent concentration*, **grams of solute** you get **per** **of solution**.

#color(blue)(|bar(ul(color(white)(a/a)"% m/v" = "mass of solute"/"100 mL solution" xx 100color(white)(a/a)|)))#

In your case, a sodium hydroxide solution is said to have a

Therefore, the volume of solution that will contain

#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(purple)("= 25% m/v")) = color(green)(|bar(ul(color(white)(a/a)3.0 * 10^2"mL"color(white)(a/a)|)))#

The answer is rounded to two **sig figs**.

Or

#### Answer:

#### Explanation:

A solution's *mass by volume percent concentration*, **per** **of solution**.

In your case, a **for every** **of solution**.

This means that you can use the solution's percent concentration as a *conversion factor* to help you determine how many milliliters would contain that many grams of sodium hydroxide.

#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(blue)("= 25% m/v")) = color(green)(|bar(ul(color(white)(a/a)color(black)(3.0 * 10^2"mL")color(white)(a/a)|)))#

The answer is rounded to two **sig figs**.