# How many mL of a 2.00M H_2SO_4 are needed to provide .250 mole of H_2SO_4?

May 29, 2016

Over $100 \cdot m L$.
$\text{Moles}$ $=$ $\text{Concentration"xx"Volume}$. This can be appreciated dimensionally, i.e. mol*L^-1xxL=mol!.
We require $0.250 \cdot m o l$, and so we divide the required number of moles by the concentration to get the volume:
$\frac{0.250 \cdot \cancel{m o l}}{2.00 \cdot \cancel{m o l} \cdot \cancel{{L}^{-} 1}} \times 1000 \cdot m L \cdot \cancel{{L}^{-} 1}$ $=$ ??mL