How many mL of a 3.2M NaOH solution is required to neutralize 74mL of a 12.4M HCl solution?
Approx. 300 mL
For all these sorts of problems we require a balanced chemical equation:
Such a scheme establishes that there is a 1:1 equivalence between moles acid and moles of base.
Thus we require a quantity of
This quantity is reasonable as the the acid is 4 times as concentrated as the base.