How many mol of NaOH are present in 66mL of 0.5M solution?

1 Answer
Apr 26, 2018

0.03mol (With sig figs)


Given that we have a 0.5M solution, that can be rewritten as 0.5mol/1 L.

Convert the 66mL to L.

#66mL * "1L"/"1000mL"# = #0.066L#

Then, multiply by the molarity to find the moles of solution.

#0.066L * "0.5mol"/"1 L" = 0.033"mol"#

With sig figs, 0.03.