# How many mol of NaOH are present in 66mL of 0.5M solution?

Apr 26, 2018

0.03mol (With sig figs)

#### Explanation:

Given that we have a 0.5M solution, that can be rewritten as 0.5mol/1 L.

Convert the 66mL to L.

$66 m L \cdot \text{1L"/"1000mL}$ = $0.066 L$

Then, multiply by the molarity to find the moles of solution.

$0.066 L \cdot \text{0.5mol"/"1 L" = 0.033"mol}$

With sig figs, 0.03.