How many moles are in 68.5 liters of oxygen gas at STP?

1 Answer
Apr 8, 2016

Answer:

It is a given that the molar volume of an ideal gas at STP is #22.414# #L*mol^-1#. This would probably even appear on a test paper as supplementary info.

Explanation:

So to get the molar quantity, we simply divide the actual volume by the molar volume:

#(68.5*cancelL)/(22.414*cancelL*mol^-1)# #=# #"approx. "3*mol#.