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How many moles of ammonia forms when 2 moles of nitrogen and 6 moles of hydrogen?

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Explanation

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Explanation:

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anor277 Share
Mar 26, 2018

Write the stoichiometric equation....and consider it...

Explanation:

$\frac{1}{2} {N}_{2} \left(g\right) + \frac{3}{2} {H}_{2} \left(g\right) \stackrel{\text{catalysis}}{\rightarrow} N {H}_{3} \left(g\right)$

And in your scenario you have mixed stoichiometric dihydrogen and dinitrogen, i.e. $2 \cdot m o l$ with respect to ${N}_{2}$, and $6 \cdot m o l$ with respect to ${H}_{2}$.

And so, given stoichiometric reaction (the which we assume for the reaction as written), we should get a $2 \cdot m o l$ quantity of ammonia.

In practice, ammonia synthesis does not enjoy such yields....however, because the product is condensable (why so?), and the reactants are largely non-condensable, a decent turnover can be achieved for this, the most important reaction performed by the chemical industry.

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