How many moles of #CO_2# are produced from 0.110 mole #O_2#?
Since no chemical equation was provided, I will assume that you're dealing with this one
#"C"_ ((s)) + "O"_ (2(g)) -> "CO"_ (2(g))#
Here carbon undergoes combustion to form carbon dioxide. Notice that it takes
This basically means that the number of moles of carbon dioxide produced by the reaction will be equal to the number of moles of oxygen gas that react, provided, of course, that you have enough moles of carbon.
Since no mention of the number of moles of carbon was made, you can safely assume that carbon is in excess.
Therefore, you have
#0.110 color(red)(cancel(color(black)("moles O"_2))) * "1 mole CO"_2/(1color(red)(cancel(color(black)("mole O"_2)))) = color(darkgreen)(ul(color(black)("0.110 moles CO"_2)))#
The answer is rounded to three sig figs.