# How many moles of CO and O_2 are required to produce 10 moles of CO_2 in the reaction 2CO + O_2 -> 2CO_2?

Jul 23, 2018

$\text{10 mol CO}$ and $\text{5 mol O"_2}$ are required to produce $\text{10 mol CO"_2}$.

#### Explanation:

Balanced equation

$\text{2CO"("g") + "O"_2("g")}$$\rightarrow$$\text{2CO"_2("g")}$

To calculate moles $\text{CO}$ and $\text{O"_2}$ required to produce $\text{10 mol CO"_2}$, multiply mol $\text{CO"_2}$ by the mol ratio between the desired reactant and $\text{CO"_2}$ in the balanced equation, with the desired reactant in the numerator.

10color(red)cancel(color(black)("mol CO"_2))xx(2"mol CO")/(2color(red)cancel(color(black)("mol CO"_2)))="10 mol CO"

10color(red)cancel(color(black)("mol CO"_2))xx(1"mol O"_2)/(2color(red)cancel(color(black)("mol CO"_2)))="5 mol O"_2"