How many moles of CO2 are in a 2 liter balloon at 27ºC at 0.82 atm? 0.00667 moles 0.067 moles 0.67 moles 0.75 moles

Question

this is what I've done so far:

n= PV/ RT

n= 0.82 atm x 2L/ 0.0821 x 300 K
but it does not match with any answer options

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Answer 1 · 2018-05-20T07:38:24

#0.067\ "mol"#

Your method is correct. Maybe there is a problem in your calculation

#"n" = "PV"/"RT"#

#"n" = "0.82 atm × 2 L"/"0.082 L atm / (mol K) × 300 K"#

#"n" = (cancel(82) × 10^-2 × 2)/(cancel(82) × 10^-3 × 300)\ "mol"#

#"n" = (2 × 10^(-2 + 3))/300\ "mol"#

#"n" = 20/300\ "mol"#

#"n" = 2/30\ "mol" = 0.067\ "mol"#