# How many moles of FeO are produced if 8 moles of SO_2 are produced in 2CuFeS_2 + 5O_2 -> 2Cu + 2FeO + 4SO_2?

Feb 6, 2017

The mole ratio $F e O \div S {O}_{2} = 2 \div 4 = 1 \div 2$, as you can see from the equation.

#### Explanation:

So: $8 m o l S {O}_{2} \leftrightarrow 4 m o l F e O$

Feb 6, 2017

$\text{4 moles of FeO}$

#### Explanation:

$\text{In every reaction we can determine amount of reactants and}$ $\text{products by using ratio formulas.}$

#"In this reaction the ratio formula =

$2 C u F e {S}_{2} : 5 {O}_{2} = 2 C u : 2 F e O : 4 S {O}_{2}$

By solving the ratio we see

$\left(2 \cdot 2 C u F e {S}_{2}\right) : \left(\frac{5}{4} \cdot 5 {O}_{2}\right) = \left(2 \cdot 2 C u\right) : \left(2 \cdot 2 F e O\right) : \left(4 \cdot 2 S {O}_{2}\right)$

$\left(4 C u F e {S}_{2}\right) : \left(6.2 {O}_{2}\right) = \left(4 C u\right) : \left(4 F e O\right) : \left(8 S {O}_{2}\right)$

Therefore FeO produced is 4 moles