How many moles of #FeO# are produced if 8 moles of #SO_2# are produced in #2CuFeS_2 + 5O_2 -> 2Cu + 2FeO + 4SO_2#?

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Answer 1 · 2017-02-06T16:04:51

The mole ratio #FeOdivSO_2=2div4=1div2#, as you can see from the equation.

So: #8 mol SO_2harr4mol FeO#

Answer 2 · 2017-02-06T16:17:53

#"4 moles of FeO"#

#"In every reaction we can determine amount of reactants and"# #"products by using ratio formulas."#

#"In this reaction the ratio formula =

#2CuFeS_2 : 5O_2 = 2Cu : 2FeO : 4SO_2#

By solving the ratio we see

#(2 * 2CuFeS_2) : (5/4 * 5O_2) = (2* 2 Cu) : (2 * 2FeO) : (4 * 2 SO_2)#

#(4CuFeS_2) : ( 6.2O_2) = (4Cu) : (4FeO) : (8SO_2)#

Therefore FeO produced is 4 moles