# How many moles of H_2SO_4 are contained in 3.5 L of a 6.5M solution?

Approx.$21 \cdot m o l$
$\text{Moles of sulfuric acid}$ $=$ $3.5 \cdot \cancel{L} \times 6.5 \cdot m o l \cdot \cancel{{L}^{-} 1}$ $=$ ??mol.
Note that including the units in the calculation as shown is a check on whether I have mulitplied or divided correctly. I wanted answer in $\text{moles}$, and the calculation returned an aswer in $\text{mol}$.