How many moles of #H_2SO_4# are contained in 3.5 L of a 6.5M solution?

1 Answer
anor277
May 18, 2016

Approx.#21*mol#

Explanation:

#"Moles of sulfuric acid"# #=# #3.5*cancel(L)xx6.5*mol*cancel(L^-1)# #=# #??mol#.

Note that including the units in the calculation as shown is a check on whether I have mulitplied or divided correctly. I wanted answer in #"moles"#, and the calculation returned an aswer in #"mol"#.

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