# How many moles of H_3PO_4 are in 94.052 grams of  H_3PO_4?

Oct 5, 2017

We gots almost $1 \cdot m o l$ $\text{phosphoric acid}$......

#### Explanation:

Given a mass, we assess the number of moles by the QUOTIENT.....

$\text{Number of moles"-="Mass"/"Molar mass of stuff}$

And note that this is consistent dimensionally, because a molar mass is reported as $g \cdot m o {l}^{-} 1$...and so we get the quotient....

$\frac{g}{g \cdot m o {l}^{-} 1} = \frac{\cancel{g}}{\cancel{g} \cdot m o {l}^{-} 1} = \frac{1}{\frac{1}{m o l}} = m o l$ as required....

And so here we take the quotient....

(94.052*g)/(97.99*g*mol^-1)=??*mol.....not quite a mole.....