# How many moles of KCI are required to prepare 1.50 L of 5.4 M KCl?

Jul 14, 2016

Why $8.1$ $\text{moles}$ of potassium chloride.
$\text{Concentration"="moles of solute"/"volume of solution}$
Since the concentration was specified to be $5.4$ mol•L^(-1), and the volume was specified to be $1.5$ $L$, the given molar quantity is appropriate for this concentration.