How many moles of Li2CO3 are produced from 88G of CO2 ?

1 Answer
Feb 27, 2018

Why 2 moles....

Explanation:

We follow the stoichiometric equation...

#Li_2O(s) + CO_2(g) rarr Li_2CO_3(g)#

There is thus 1:1 equivalence between the carbon dioxide and the lithium carbonate.

#"Moles of carbon dioxide"=(88*g)/(44.0*g*mol^-1)=2*mol#.

And thus a mass with respect to #"lithium carbonate"# of...

#2*molxx73.89*g*mol^-1=147.8*g...#