# How many moles of lithium nitrate are in 256 mL of a 0.855 M solution?

Jul 1, 2016

There are 0.219 mol of $L i N {O}_{3}$ in 256 mL of 0.855 M solution.

#### Explanation:

Molarity is represented by the formula below:

We already have the molarity and the volume of solution. However, the volume does not have the proper units since it is given in terms of milliliters instead of liters.

We can convert 256 mL into liters by using the conversion factor 1000mL = 1L. When 256mL is divided by 1000 mL, we obtain a volume of 0.256 L.

Now we can rearrange the equation to solve for the number of moles. We can do this by multiplying by L solution on both sides of the equation. The L solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume like so:

Moles of solute = (L solution) * (Molarity)

Now we just plug the known values in!

Moles of solute = (0.256 L) (0.855M) = 0.219 moles