How many moles of oxygen gas will occupy a volume of 2.5 liters at 1.2 atm and 298K?

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Answer 1 · 2018-01-11T15:00:42

#0.122# moles of oxygen gas #(O_2)#

We need to use the ideal gas law for this problem, which states that:

#PV=nRT#

#P# is pressure in atmospheric pressures (in this case)

#V# is volume in liters (in this case)

#n# is moles of the substance

#R# is the gas constant (for this case, we use #0.082 l \ atm \ mol^-1 K^-1#)

#T# is the temperature in Kelvin (as always)

Plugging in the known values, #V=2.5l#, #P=1.2atm#, #T=298K#, we get

#n=(PV)/(RT)=(1.2*2.5)/(298*0.082)~~0.122# moles

So, there will be #0.122# moles of oxygen gas.