# How many moles of phosphorus trichloride would contain 3.35 times 10^24 molecules of phosphorus trichloride?

Jun 12, 2017

The answer is $\text{5.56 mol PCl"_3}$.
One mole of molecules is $6.022 \times {10}^{23}$ molecules.
Divide the number of molecules of $\text{PCl"_3}$ by (6.022xx10^23"molecules")/"mol" by multiplying by its inverse.
$3.35 \times {10}^{24} \text{molecules PCl"_3xx(1"mol PCl"_3)/(6.022xx10^23"molecules PCl"_3)="5.56 mol PCl"_3}$ rounded to three sig figs