# How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution?

Aug 22, 2016

$\text{% by mass}$ $=$ "mass of solute"/"mass of solution"xx100%

#### Explanation:

Thus if "% by mass"=85%, there are 85.5%xx155*g" solute" in a solution whose mass is $155 \cdot g$.

$\text{Moles of NaCl}$ $=$ (85.5%xx155*g)/(58.44*g*mol^-1)

$=$ $2.27 \cdot m o l \text{ with respect to NaCl}$.

This result makes no chemical sense at all inasmuch as I do not think you can prepare a solution of sodium chloride with that concentration. C'est la vie.