# How many moles of solute are contained in 200 milliliters of a 1 M solution?

May 29, 2016

#### Answer:

Such a volume contains $0.200$ $m o l$ of solute.

#### Explanation:

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$.

Typically, we perform the calculation: $C = \frac{n}{V}$, where $n$ is the amount of solute in moles, $V$ the volume of the solution in $\text{litres}$, and $C$, the concentration in $m o l \cdot {L}^{-} 1$.

Given $C = \frac{n}{V}$, then $n$ $=$ $C \times V$.

Here, $n$ $=$ $200 \times {10}^{-} 3 \cdot L \times 1 \cdot m o l \cdot {L}^{-} 1$ $=$ $0.200 \cdot m o l$. This calculation is consistent dimensionally, as when $L$ cancel, we get an answer in $m o l$.