# How many moles of zinc oxide is produced if 4.44 moles of zinc reacts with excess oxygen?

Dec 19, 2016

Why $4.44$ $m o l$ precisely.
$Z n \left(s\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow Z n O \left(s\right)$
And thus between the oxide and the starting metal, there is clearly $1 : 1$ equivalence. So if there are 4.44 moles of zinc, clearly there are 4.44 moles of oxide. If 10 moles of zinc oxide were produced, then how moles of zinc were used?