# How many mols CaCO_3 can be dissolved in .0250 mol HCl in the equation CaCO_3 + 2HCl -> CaCl_2 + H_2O + CO_2?

Apr 9, 2016

$0.0125 m o l C a C {O}_{3}$

#### Explanation:

The equation says

$C a C {O}_{3} + 2 H C l$,

which means that for every $2$ moles of $H C l$ there is one of $C a C {O}_{3}$. This is called the molar ratio, in this case $2 : 1$.

We know that there are $0.0250$ moles of $H C l$, which is equal to two parts in the ratio. If $0.0250$ is two parts, then one part must be $0.0125$.

And, since there is only one part of $C a C {O}_{3}$ in the ratio, then you can dissolve $0.0125$ moles of $C a C {O}_{3}$ in $0.0250$ moles of $H C l$.