How many mols #CaCO_3# can be dissolved in .0250 mol #HCl# in the equation #CaCO_3 + 2HCl -> CaCl_2 + H_2O + CO_2#?

1 Answer
Apr 9, 2016

Answer:

#0.0125molCaCO_3#

Explanation:

The equation says

#CaCO_3 + 2HCl#,

which means that for every #2# moles of #HCl# there is one of #CaCO_3#. This is called the molar ratio, in this case #2:1#.

We know that there are #0.0250# moles of #HCl#, which is equal to two parts in the ratio. If #0.0250# is two parts, then one part must be #0.0125#.

And, since there is only one part of #CaCO_3# in the ratio, then you can dissolve #0.0125# moles of #CaCO_3# in #0.0250# moles of #HCl#.