How many real number solutions are there for #x^2 - 6 = 0#?

1 Answer
George C.
Aug 2, 2017

#2#

Explanation:

The equation:

#x^2-6=0#

has two real number solutions:

#x=sqrt(6)" "# and #" "x=-sqrt(6)#

#sqrt(6)# is the principal square root of #6# and is positive.

#-sqrt(6)# is the non-principal square root of #6# and is negative.

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