# How many terms are in this expression 5(-4a+8b+7c)-3(5b-11c-32)?

Aug 3, 2017

There are $2$ terms

#### Explanation:

There are $2$ terms.

Terms are separated by plus and minus signs unless the signs are
- in a bracket
- in a fraction
- under a root

$\textcolor{red}{5 \left(- 4 a + 8 b + 7 c\right)} \textcolor{b l u e}{- 3 \left(5 b - 11 c - 32\right)}$

If the brackets are multiplied out we get $6$ terms.

$= \textcolor{g r e e n}{- 20 a} \textcolor{m a \ge n t a}{+ 40 b} \textcolor{\lim e}{+ 35 c} \textcolor{m a \ge n t a}{- 15 b} \textcolor{\lim e}{+ 33 c} \textcolor{p u r p \le}{+ 96}$

If the like terms are added, we get $4$ terms

$= \textcolor{g r e e n}{- 20 a} \textcolor{m a \ge n t a}{+ 25 b} \textcolor{\lim e}{+ 68 c} \textcolor{p u r p \le}{+ 96}$