How much ammonia (NH3) can be obtained when 3.0g H2 reacts with 100g N2?

1 Answer
Dec 1, 2015

Answer:

Approx. #8*g#.

Explanation:

We need (i), a reaction scheme:

#1/2N_2(g) + 3/2H_2 rarr NH_3(g)#

And (ii), molar quantities of each reagent:

#H_2#, #(3.0*g)/(2*g*mol^-1)# #=# #3/2*mol# #H_2#;

#N_2#, #(100.0*g)/(28*g*mol^-1)# #=# #3.3*mol# #N_2#;

Clearly, dihydrogen is in deficiency, and dinitrogen is in vast excess. So at most we can make #1/3# #xx# #3/2*mol# #=# #1/2# #mol# ammonia, # ~~# #8*g#.

Vast quantities of ammonia are synthesized industrially. Why is this an important reaction?