# How much energy is absorbed as heat by 21 g of gold when it is heated from 25°C to 35°C?

Jan 3, 2016

$q = 27.09 J$

#### Explanation:

The amount of heat absorbed by the system could be calculated by:

$q = m \times s \times \Delta T$

where,
$q$ is the heat,
$m$ is the mass of the gold sample,
$s = 0.129 \frac{J}{g {\cdot}^{\circ} C}$ is the specific heat capacity of gold
and $\Delta T = {T}_{f} - {T}_{i} = {35}^{\circ} - {25}^{\circ} = {10}^{\circ} C$ is the change on temperature of the sample.

=>q=21cancel(g)xx0.129 J/(cancel(g)*cancel(""^@C))xx10cancel(""^@C)=27.09 J