How much energy is absorbed as heat by 21 g of gold when it is heated from 25°C to 35°C?

1 Answer
Jan 3, 2016

Answer:

#q=27.09 J#

Explanation:

The amount of heat absorbed by the system could be calculated by:

#q=mxxsxxDeltaT#

where,
#q# is the heat,
#m# is the mass of the gold sample,
#s=0.129 J/(g*^@C)# is the specific heat capacity of gold
and #DeltaT=T_f-T_i=35^@-25^@=10^@C# is the change on temperature of the sample.

#=>q=21cancel(g)xx0.129 J/(cancel(g)*cancel(""^@C))xx10cancel(""^@C)=27.09 J#

Here is a video that explains more about this topic:
Thermochemistry | Enthalpy and Calorimetry.