How much heat (in kJ) is needed to convert 866 g of ice at -10˚C to steam at 126 ˚C? (The specific heats of ice and steam are 2.03 J/g. ˚C and 1.99 J/g. ˚C, respectively.)
This'll be a bit lengthy so bear with me.
This problem will require 5 values;
The heat required to raise the ice to its melting point (0°C),
The heat required to melt all of said ice,
The heat required to raise the temperature of the water to its boiling point (100°C),
The heat required to vaporize all the water,
And the heat required to raise the temperature of the steam to 126°C,
We can find every value using
I'll now write out every equation with the given info.
Note: in the 3rd and 4 equations, 334J/g and 2260J/g are the heat of fusion and vaporization of water respectively.
After calculating and using sig figs in each equation, we are given 5 values:
After adding all the values, we have a total of 2714000J, or 2714kJ required for the conversion.