# How much heat is given off when 1.25 grams of silver is cooled from 100.0 C to 80.0 C?

## The specific heat of silver is O.057 cal/g C

Dec 24, 2017

The heat is $=$ $\text{1.43 cal}$.

#### Explanation:

Use

$q = m \times s \times \Delta T$

Here the mass, $m$, is $\text{1.25 g}$, the specific heat, $s$, is ${\text{0.057 cal g"^(-1) ""^@"C}}^{- 1}$ , and

$\Delta T = | {80.0}^{\circ} \text{C" - 100^@"C"| = 20^@"C}$

So

$\text{Heat liberated" = 1.25 xx 0.057 xx 20 = "1.43 cal}$