How much heat is required to change 40 g of water by 25℃? (c= 4.18 J/g℃)

1 Answer
May 6, 2018

We're putting heat into the system, this is an endothermic process.

Given,

#m = 40"g"#

#DeltaT = 25°"C"#

#C_"s" = (4.18"J")/("g"*°"C")#

Recall,

#q = mC_"s"DeltaT#

Hence,

#q = mC_"s"DeltaT approx 4.2*10^3"J"#

of heat must be put into that mass of water to "heat" it.