How much heat is required to raise the temp of 654 g of water from 34.5°C to 89.7°C?

1 Answer
Apr 24, 2016

Answer:

#151kJ#

Explanation:

Amount of energy needed to raise a certain amount of a substance is given by

#E=m*c*theta#

where #E# is energy, #m# is mass, #c# is the specific heat capacity and #theta# is the change in temperature.

The specific heat capacity of water is #4181J/(kg ^oC)#.

Mass is given as #654g#, which in the more useful unit of kilograms is #0.654kg#.

Change in temperature is also given in the question indirectly, and can be calculated as the difference in the two values, or #89.7-34.5=55.2^oC#.

Plugging these values into the equation,

#E=0.654kg*4181J/(kg^oC)*55.2^oC=150937J#

#approx151kJ#