How much heat is required to warm 1.60 kg of sand from 22°C to 100°C?

1 Answer
May 3, 2016

Answer:

The energy required to heat the sand by #78^@"C"# is #~~##"36000 J"#.

Explanation:

The specific heat capacity for sand, #c#, is #"0.290 J/g"^@"C"#.
http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html

The equation for determining the heat required to increase the temperature of the sand is #Q=cmDeltaT#, where #Q# is heat energy in Joules, #m# is mass in grams, #c# is specific heat capacity, and #Delta T# is the change in temperature, #(T_"final"-T_"initial")#.

#Delta T=(100^@"C")-(22^@"C")=78^@"C"#

Mass of sand in grams:

#1.60cancel"kg"xx(1000"g")/(1cancel"kg")="1600 g"#

Substitute the given values into the equation.

#Q=(0.290"J/g"^@"C")xx(1600"g")xx(78^@"C")="36000 J"# (rounded to two significant figures)