# How much heat would be needed to raise the temperature of 25.0 g of water by 18"^@C?

Aug 18, 2017

$1.9 \cdot {10}^{3}$ J.

#### Explanation:

The specific heat of water is 4.18 J/(g·°C).

This means that it takes 4.18 J to raise one gram of water one degree.

Multiply that by 25.0 g and 18°C.

$\frac{4.18 J}{g \cdot K} \cdot 25.0 g \cdot 18 K$

The units cancel out and you get joules.

18 °C has 2 sig figs, so you give your answer to 2 sig figs.

$1.9 \cdot {10}^{3}$ J.