How much heat would be needed to raise the temperature of 25.0 g of water by 18#"^@#C?

1 Answer


#1.9*10^3# J.


The specific heat of water is 4.18 J/(g·°C).

This means that it takes 4.18 J to raise one gram of water one degree.

Multiply that by 25.0 g and 18°C.

#(4.18J)/(g*K) *25.0g*18K#

The units cancel out and you get joules.

18 °C has 2 sig figs, so you give your answer to 2 sig figs.

#1.9*10^3# J.