How much power is produced if a voltage of #12 V# is applied to a circuit with a resistance of #24 Omega#?

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Answer 1 · 2018-06-30T16:30:59

#P = 6 W#

There are 3 variations of the power formula:

#P = V*I, " "P = I^2*R, " and " P = V^2/R#

If you know any one of them, the others are available thru the use of Ohm"s Law and a bit of algebra.

For this problem, use #P = V^2/R#

#P = (12 V)^2/(24 Omega) = 6 V^2/Omega = 6 W#

I hope this helps,
Steve

Answer 2 · 2018-07-02T13:50:09

#6# watts

Power in this case is given by the equation:

#P=V^2/R#

where:

#P# is the power in watts

#V# is the voltage in volts

#R# is the resistance in ohms

So, we get:

#P=(12 \ "V")^2/(24 \ Omega)#

#=(144 \ "V"^2)/(24 \ Omega)#

#=6 \ "W"#