How much power is produced if a voltage of 5 V is applied to a circuit with a resistance of 96 Omega?

Apr 7, 2018

The power is approximately $0.26$ Watts

Explanation:

Let $I =$ current, $P =$ power, $V =$ voltage, and $R =$ resistance.

Ohm's law states

$V = I R$

We can solve this for current.

$I = \frac{V}{R}$

We also know that

$P = I V$.

We can eliminate the current with Ohm's Law.

$P = {V}^{2} / R = {5}^{2} / 96 \approx 0.26$ Watts

Apr 8, 2018

Around $0.26$ watts

Explanation:

Ohm's law states that,

$V = I R$

• $I$ is the current in amperes

• $R$ is the resistance in ohms

$\iff I = \frac{V}{R}$

Meanwhile, power is measured through,

$P = I V$

• $V$ is the voltage in volts

$\iff I = \frac{P}{V}$

Through the two equations, we get a relationship:

$\frac{V}{R} = \frac{P}{V}$

$P = {V}^{2} / R$

Now, we can simply plug in the values, and get:

$P = {\left(5 \setminus \text{V}\right)}^{2} / \left(96 \setminus \Omega\right)$

$= \frac{25 \setminus {\text{V}}^{2}}{96 \setminus \Omega}$

$\approx 0.26 \setminus \text{W}$