# How much water is needed to prepare a .50 molal solution using 0.50 moles of sodium chloride?

May 30, 2018

$1 k g$

#### Explanation:

($b$ is the symbol for molality, and molality is the number of moles of solute per kilogram of solvent)

$b = \frac{n}{m}$

$0.5 = \frac{0.5}{m}$

$m = 1 k g$