How much work would it take to push a 5 kg weight up a 1 m plane that is at an incline of pi / 6 ?

1 Answer
Mar 28, 2016

W=4.33 (kg*m)/s^2

Explanation:

Given:
m=5 kg
a=1m
d=1m
theta=pi/6

We know:

W=F*d*costheta

W= m*a*d*costheta

W= 5*1*1*cos(pi/6)

W=5*cos(root_3/2)

W= 5*0.8660

W=4.33 (kg*m)/s^2