How to calculate log (1÷0.8500)?

1 Answer
anor277
Feb 21, 2018

You want #log_10(1/0.8500)#?

Explanation:

..or #log_e(1/0.8500)#...if you don't specify a base a non-chemist might assume natural logarithms....we assume that it is #log_10#.

So #log_10(1/0.8500)=log_(10)1-log_10(0.8500)=#

#=0-(-0.070758)=+0.07058#...

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