How to calculate the concentration of Ca(OH)2 if the pH of this solution is 9.2?

1 Answer
anor277
Feb 10, 2018

Well, (i) we calculate #[HO^-]#

Explanation:

...we are given that #pH=9.20#...and thus #pOH=14.0-9.20=4.80#..

And so #[HO^-]=10^(-4.80)=1.58xx10^-5*mol*L^-1#..

And (ii), we write a reaction that represents the speciation of calcium hydroxide in aqueous solution....

#Ca(OH)_2(s) stackrel(H_2O)rarrunderbrace(Ca^(2+) + 2HO^-)_(Ca(OH)_2(aq))#

And so #[Ca(OH)_2(aq)]=1/2[HO^-]=7.92xx10^-6*mol*L^-1#

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